Explorar o código

不以套餐id查询是否重复订阅

peng hai 1 ano
pai
achega
4a2d368f65
Modificáronse 1 ficheiros con 1 adicións e 1 borrados
  1. 1 1
      AdminController/ServeManagementController.py

+ 1 - 1
AdminController/ServeManagementController.py

@@ -2020,7 +2020,7 @@ class serveManagement(View):
                         if not unused_meal_qs.exists():
                         if not unused_meal_qs.exists():
                             UID_Bucket.objects.filter(uid=uid).update(has_unused=0, updateTime=nowTime)
                             UID_Bucket.objects.filter(uid=uid).update(has_unused=0, updateTime=nowTime)
                         return response.json(0)
                         return response.json(0)
-                    unused_uid_Meal_qs = Unused_Uid_Meal.objects.filter(uid=uid, bucket_id=bucket_id)
+                    unused_uid_Meal_qs = Unused_Uid_Meal.objects.filter(uid=uid, bucket_id=bucket_id, order_id='')
                     if unused_uid_Meal_qs.exists():  # 如果通过uid查询到未使用套餐则删除套餐
                     if unused_uid_Meal_qs.exists():  # 如果通过uid查询到未使用套餐则删除套餐
                         unused_uid_Meal_qs.first().delete()
                         unused_uid_Meal_qs.first().delete()
                         unused_meal_qs = Unused_Uid_Meal.objects.filter(uid=uid)
                         unused_meal_qs = Unused_Uid_Meal.objects.filter(uid=uid)